Prior to
having
the
radiation act,
we
adjust
the
bridge
wire to
zero
current.
We
have then
*1(*«)o
"
*2*3
=
0.
If
one
lets the radiation act,
W4
changes and
one
obtains
a
current
I in the
bridge.
We
have then
-
,
*1*.
~
*2*3
ir
-
e
.
However,
=
(W4)0(l
+
at).
If this is substituted,
the
numerator and denominator
will
change.
I
=
e
1
*12*«0
-
*2*3)
+
*i(*«)o**
_
,
*1
*40a£f,
_
4*1
Since the temperature difference is supposed to
be
small,
apparently
one
can put
1
- atN
=
1,
thus very closely
wiw40
at.
We
have, however,
dPi
=SO'dz -ho tdz =Kc cit.
tot
O'
is the irradiated surface,
S
the radiation intensity, i.e., the
quantity of heat striking in unit time the unit surface area
whose
normal has
a
direction opposite to that of the rays,
t
is the
temperature difference relative to the surroundings.
hO
I$Q~
tot
1 -
___tldz
-
Nc
3
a b
cit
dz
1
z
+
C
-
F
Ig
(a
-
bt).
The
boundary cond[ition] yields
C
-~lga
1
ía
=
~-
ig
a bz
=e
a
115
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