DOC. 14 EINSTEIN AND
BESSO MANUSCRIPT
367
[p. 4]
(Einstein)
[15]Page number
in
Besso's hand.
[16][P.
4]
shows
a
step-by-step
derivation of
equations
for N and
T (introduced
in
[eq. 17] on
[p.
3])
from
[eq.
20]
on [p.
3].
[17]Correction
from
1/r to
r
in
Besso's hand.
[18][Eq. 30]
is
written
over
two lines, the
left-hand side
on
the first
line,
the
right-hand
side
on
the
second. The
equality
sign
between
the two is
omitted. The
equation
is
obtained
as
follows.
The
starting point is
[eq.
20]
on [p.
3].
This
equation
is
multiplied
by
minus
one. Evaluating
the
derivative
in (minus) the
right-hand
side
of
[eq.
20],
one
arrives
at
the
right-hand
side
of
[eq.
30].
[Eq.
27]
is
substituted for
(minus) the
left-hand
side
of
[eq.
20] (see
[p.
3],
[eq.
17]).
[Eqs.
28-29]
are
then
used
for
the two
parts
of
[eq.
27].
In this
way, one
arrives
at the
left-hand
side
of
[eq.
30].
As
is
indicated
by
the
upbrackets,
[eq.
30] is split
up
into two
equations
on
the
assumption
that
the
coefficients of
x2
on
the left- and
right-hand sides
are
equal
to each
other
(on
[p. 3]
the
same was
done
(see note
13)).
The
first equation
contains
both
N
and T, the
second
only
contains N.
[19]It
is verified
that
N(r)
=
1/8A2/r2 is
a
solution
of
the
second
equation
coming out
of
[eq. 30]
(see
note
18).
[20]The
material
in the
lower left
corner
is
in
Besso's hand.