D O C . 5 1 5 C A L C U L A T I O N S 8 0 9 Elliptischer Zusammenhang entsprechen ein- ander. Die g und 1. Ableitungen sollen überall stetig sein. _____________________________________________________________ AD. [2 100.1]. Written on the verso of p. 5 (“Nachtrag”) of Doc. 516. r, ϑ ϕ und R r, π – ϑ ϕ – π + μ ν σ 0, wenn μ ν σ ≠ ≠ = 0 0 0 0= 1 1 1 1∂g11 2∂x1 -- - = 2 2 2 0= 3 3 3 0= 0 0 1 1∂g00 2∂x1 -- - – 1 2dr -- - d f 2 – = = 1 1 0 0= 2 2 0 0= 3 3 0 0= 0 1 0 1∂g00 2∂x1 -- - 1 2dr - d f 2 –-- = = 1 0 1 0= 2 0 2 0= 3 0 3 0= 0 0 2 1∂g00 2∂x2 -- - – 0 = = 1 1 2 0= 2 2 1 + 1 2dr -- - d U2 = 3 3 2 U2 cosϑ sinϑ = 0 2 0 1∂g00 2 ---- ∂x2 0 = = 1 2 1 0= 2 1 2 1 2dr -- - d U2 –= 3 2 3 U2 cosϑ sinϑ –= 0 0 3 1∂g00 2∂x3 -- - – 0 = = 1 1 3 0= 2 2 3 0= 3 3 1 +-- 1 2dr - d U2sin2ϑ = 0 3 0 + 1∂g00 2∂x3 -- - 0 = = 1 3 1 0= 2 3 2 0= 3 1 3 1 2dr -- - d U2sin2ϑ –= Γ00 1 1 2dr -- - d f 2 = Γ22 1 1 2dr -- - d U2 –= Γ33 2 cosϑ sinϑ –= Γ33 1 1 2dr -- - d U2sin2ϑ –= Γ01 0 1 2f -- - 1 2dr --- - d f 2 = Γ21 2 1 2U2dr -- - 1 ------ d U2 = Γ32 3 cosϑ sinϑ ------------ = Γ31 3 1 2U2dr -- - 1 ------ d U2 = Γ00 2 1 2U2dr -- - 1 ------ d f 2 = Γ20 0 =