DOC.
462
FEBRUARY
1918 471
462. From Max Planck
Grunewald,
13 February 1918
Dear
Colleague,
It
is
how
I
had
suspected.
If
for
a
quasi-elastic
central motion
the
Lagrangian
function
is L
=
T
-
U
(T
kinetic,
U potential
energy)
and
m
is
the
mass
of
the
oscillating point,
then
0L/0m
is
the
“force”
that
must be
exerted
externally
so
that
m
remains constant
during
the
motion.
If,
furthermore,
a
is
the constant
for
the
quasi-elastic
force,
then
-dL/da
is
the
force
that
must
be exerted
externally so
that
a
remains constant.
(With
natural
motion,
m
and
a
obviously
are
constant because
they
have
pre-
scribed
values,
in
the
sense
of
firm
conditional
equations linking
the
coordinates.)
If,
now,
m
and
a
are
simultaneously
altered such
that the
relation
m/a
remains
unchanged,
and
the
period along
with
it,
then
dm/da=m/a.
Then
the total
work exerted from outside
upon
the
system is:
A
=
dL dL
8a
-z-om
-
-8a
=--
dm da
a
(
dL dL
\
=-~•L,
because
dL/dm=T/m
and
dL/da=-U/a.
Consequently,
the
temporal
mean
value
A
for
one
period
=
0 (because
T
=
U).
From this
follows that, for
the
reversible adiabatic
change
in
state
under
consideration,
the
energy
of
the
system
(T
+
U)
does not
change,
hence
neither
does its half: T. And since
the
period
also does
not
change,
the
time
integral of
T
does in
fact
remain invariant
throughout
a
period.
I
thus think that the adiabatic
hypothesis can very
well
be
applied
to
changes
in
mass
without
encountering an
inconsistency.[1]
Good-bye
until
Saturday
the 23rd.
Cordial
regards,
yours,
Planck.
Previous Page Next Page

Extracted Text (may have errors)


DOC.
462
FEBRUARY
1918 471
462. From Max Planck
Grunewald,
13 February 1918
Dear
Colleague,
It
is
how
I
had
suspected.
If
for
a
quasi-elastic
central motion
the
Lagrangian
function
is L
=
T
-
U
(T
kinetic,
U potential
energy)
and
m
is
the
mass
of
the
oscillating point,
then
0L/0m
is
the
“force”
that
must be
exerted
externally
so
that
m
remains constant
during
the
motion.
If,
furthermore,
a
is
the constant
for
the
quasi-elastic
force,
then
-dL/da
is
the
force
that
must
be exerted
externally so
that
a
remains constant.
(With
natural
motion,
m
and
a
obviously
are
constant because
they
have
pre-
scribed
values,
in
the
sense
of
firm
conditional
equations linking
the
coordinates.)
If,
now,
m
and
a
are
simultaneously
altered such
that the
relation
m/a
remains
unchanged,
and
the
period along
with
it,
then
dm/da=m/a.
Then
the total
work exerted from outside
upon
the
system is:
A
=
dL dL
8a
-z-om
-
-8a
=--
dm da
a
(
dL dL
\
=-~•L,
because
dL/dm=T/m
and
dL/da=-U/a.
Consequently,
the
temporal
mean
value
A
for
one
period
=
0 (because
T
=
U).
From this
follows that, for
the
reversible adiabatic
change
in
state
under
consideration,
the
energy
of
the
system
(T
+
U)
does not
change,
hence
neither
does its half: T. And since
the
period
also does
not
change,
the
time
integral of
T
does in
fact
remain invariant
throughout
a
period.
I
thus think that the adiabatic
hypothesis can very
well
be
applied
to
changes
in
mass
without
encountering an
inconsistency.[1]
Good-bye
until
Saturday
the 23rd.
Cordial
regards,
yours,
Planck.

Help

loading