44
DOC.
37
OCTOBER
1914
Your
integrating apparatus
appeals
to
me
very
much.
Although,
as
it
is
described,
it
only
delivers
y
dx;
but
you
intended-if
I
have
understood
you
correctly-to turn it into
a
measuring
device for
J
y1y2dx
which
you
activate
through
engaging a
second
adjustable
friction clutch
so
that
the rotation of
the
planimeter
disk
is not
simply
proportional
to
dx,
but
propor-
tional
to
y2dx;
then,
of
course,
the
rotation of
the little
counter wheel becomes
proportional
to
y1y2dx.
Another
possibility
with which
you
could
manage
with
a
friction element
but
which would
require
two
integral operations
instead
would be
the
following:
You
have
an
instrument
in which
the
distance of
your
friction roll to
the
center
of
your
counter disk is
proportional
to
y2
(whether
this
is
easily realizable,
I
do not
know).
With
such
a
device
you
could
measure
f(y1+y2)2dx
and
ƒ(y1-y2)2dx,
thus
also
the
difference[6]
2/y1y2dx.
The construction
of
such
a
device
does
not
appear
to
me
to
be
particularly dif-
ficult.
When
we
meet
again,
we
could,
if
you
have
the
inclination
and the
time,
weigh
the
various
possibilities against one
another.
I
ask in advance for
your
forbearance, knowing
well
that
I
am a low-grade
dilettante
in such matters.
With
regards
from
your very
devoted
colleague,
A.
Einstein.
Previous Page Next Page

Extracted Text (may have errors)


44
DOC.
37
OCTOBER
1914
Your
integrating apparatus
appeals
to
me
very
much.
Although,
as
it
is
described,
it
only
delivers
y
dx;
but
you
intended-if
I
have
understood
you
correctly-to turn it into
a
measuring
device for
J
y1y2dx
which
you
activate
through
engaging a
second
adjustable
friction clutch
so
that
the rotation of
the
planimeter
disk
is not
simply
proportional
to
dx,
but
propor-
tional
to
y2dx;
then,
of
course,
the
rotation of
the little
counter wheel becomes
proportional
to
y1y2dx.
Another
possibility
with which
you
could
manage
with
a
friction element
but
which would
require
two
integral operations
instead
would be
the
following:
You
have
an
instrument
in which
the
distance of
your
friction roll to
the
center
of
your
counter disk is
proportional
to
y2
(whether
this
is
easily realizable,
I
do not
know).
With
such
a
device
you
could
measure
f(y1+y2)2dx
and
ƒ(y1-y2)2dx,
thus
also
the
difference[6]
2/y1y2dx.
The construction
of
such
a
device
does
not
appear
to
me
to
be
particularly dif-
ficult.
When
we
meet
again,
we
could,
if
you
have
the
inclination
and the
time,
weigh
the
various
possibilities against one
another.
I
ask in advance for
your
forbearance, knowing
well
that
I
am a low-grade
dilettante
in such matters.
With
regards
from
your very
devoted
colleague,
A.
Einstein.

Help

loading