D O C U M E N T 5 2 3 M AY 1 9 2 9 4 5 1 523. To Chaim Herman Müntz [around or after mid-May 1929][1] Dear Mr. Müntz, I begin with The S are found by cyclic shifts of the , , . Now, I set That gives Now, vanishes, because the first factor is symmetric and the second is antisymmetric in  and . Likewise, the same occurs with the second term in the first parenthesis. Thus, the whole contribution of the first parenthesis vanishes. Now, however, we have . What remains is therefore    h s h s   h s   –   =         /        ,    ,    S    S   S      – S      – – = S         1 2 S        // =   or or h s h s     h s h s     –     h s   h s   h s   h s   –     + h s       h s     h s      s     –h = 2h s   h s      l m i  lm  i  m l i – + S   S    km i l  im k l –  im l k  lm i k – h s  h     h s   h s   –   h t   h t   –    S   S   h s h s   h s   –   h t  h T   h T   –           h s, h s   h s   –   1 2 -- h s   h s   –   h t, h t, –  h s  h t            |    |    |    – –